4(15-ah)+2s=52

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Solution for 4(15-ah)+2s=52 equation:


Simplifying
4(15 + -1ah) + 2s = 52
(15 * 4 + -1ah * 4) + 2s = 52
(60 + -4ah) + 2s = 52

Solving
60 + -4ah + 2s = 52

Solving for variable 'a'.

Move all terms containing a to the left, all other terms to the right.

Add '-60' to each side of the equation.
60 + -4ah + -60 + 2s = 52 + -60

Reorder the terms:
60 + -60 + -4ah + 2s = 52 + -60

Combine like terms: 60 + -60 = 0
0 + -4ah + 2s = 52 + -60
-4ah + 2s = 52 + -60

Combine like terms: 52 + -60 = -8
-4ah + 2s = -8

Add '-2s' to each side of the equation.
-4ah + 2s + -2s = -8 + -2s

Combine like terms: 2s + -2s = 0
-4ah + 0 = -8 + -2s
-4ah = -8 + -2s

Divide each side by '-4h'.
a = 2h-1 + 0.5h-1s

Simplifying
a = 2h-1 + 0.5h-1s

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