4(15-z)=28

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Solution for 4(15-z)=28 equation: 



4(15-z)=28

We move all terms to the left:

4(15-z)-(28)=0

We add all the numbers together, and all the variables

4(-1z+15)-28=0

We multiply parentheses

-4z+60-28=0

We add all the numbers together, and all the variables

-4z+32=0

We move all terms containing z to the left, all other terms to the right

-4z=-32

z=-32/-4

z=+8

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