4(19x+3)+4x=6x+12

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Solution for 4(19x+3)+4x=6x+12 equation: 



4(19x+3)+4x=6x+12

We move all terms to the left:

4(19x+3)+4x-(6x+12)=0

We add all the numbers together, and all the variables

4x+4(19x+3)-(6x+12)=0

We multiply parentheses

4x+76x-(6x+12)+12=0

We get rid of parentheses

4x+76x-6x-12+12=0

We add all the numbers together, and all the variables

74x=0

x=0/74

x=0

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