4(1c+4)=61+1c

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Solution for 4(1c+4)=61+1c equation: 



4(1c+4)=61+1c

We move all terms to the left:

4(1c+4)-(61+1c)=0

We add all the numbers together, and all the variables

4(c+4)-(c+61)=0

We multiply parentheses

4c-(c+61)+16=0

We get rid of parentheses

4c-c-61+16=0

We add all the numbers together, and all the variables

3c-45=0

We move all terms containing c to the left, all other terms to the right

3c=45

c=45/3

c=15

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