4(1x+3)-4=8(1/2x+1)

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Solution for 4(1x+3)-4=8(1/2x+1) equation: 



4(1x+3)-4=8(1/2x+1)

We move all terms to the left:

4(1x+3)-4-(8(1/2x+1))=0



Domain of the equation: 2x+1))!=0

x∈R



We add all the numbers together, and all the variables

4(x+3)-(8(1/2x+1))-4=0

We multiply parentheses

4x-(8(1/2x+1))+12-4=0

We multiply all the terms by the denominator


4x*2x+12*2x+1))-4*2x+1))+1))-(8(1=0

Wy multiply elements

8x^2+24x+1))-4*2x+1))+1))-(8(1=0

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