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4(1x-3)+7=5(1x-1)-1x
We move all terms to the left:
4(1x-3)+7-(5(1x-1)-1x)=0
We add all the numbers together, and all the variables
4(x-3)-(5(x-1)-1x)+7=0
We multiply parentheses
4x-(5(x-1)-1x)-12+7=0
We calculate terms in parentheses: -(5(x-1)-1x), so:We add all the numbers together, and all the variables
5(x-1)-1x
We add all the numbers together, and all the variables
-1x+5(x-1)
We multiply parentheses
-1x+5x-5
We add all the numbers together, and all the variables
4x-5
Back to the equation:
-(4x-5)
4x-(4x-5)-5=0
We get rid of parentheses
4x-4x+5-5=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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