4(2)+3z(2)+6=26

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Solution for 4(2)+3z(2)+6=26 equation: 



4(2)+3z(2)+6=26

We move all terms to the left:

4(2)+3z(2)+6-(26)=0

We add all the numbers together, and all the variables

3z^2+22=0

a = 3; b = 0; c = +22;
Δ = b2-4ac
Δ = 02-4·3·22
Δ = -264
Delta is less than zero, so there is no solution for the equation

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