4(2*0+1)=12*0+2-4*0+2

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Solution for 4(2*0+1)=12*0+2-4*0+2 equation: 


Simplifying
4(2 * 0 + 1) = 12 * 0 + 2 + -4 * 0 + 2

Multiply 2 * 0
4(0 + 1) = 12 * 0 + 2 + -4 * 0 + 2

Anything times zero is zero.
4(0 + 1) = 12 * 0 + 2 + -4 * 0 + 2

Combine like terms: 0 + 1 = 1
4(1) = 12 * 0 + 2 + -4 * 0 + 2

Multiply 4 * 1
4 = 12 * 0 + 2 + -4 * 0 + 2

Multiply 12 * 0
4 = 0 + 2 + -4 * 0 + 2

Anything times zero is zero.
4 = 0 + 2 + -4 * 0 + 2

Multiply -4 * 0
4 = 0 + 2 + 0 + 2

Anything times zero is zero.
4 = 0 + 2 + 0 + 2

Combine like terms: 0 + 2 = 2
4 = 2 + 0 + 2

Combine like terms: 2 + 0 = 2
4 = 2 + 2

Combine like terms: 2 + 2 = 4
4 = 4

Add '-4' to each side of the equation.
4 + -4 = 4 + -4

Combine like terms: 4 + -4 = 0
0 = 4 + -4

Combine like terms: 4 + -4 = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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