4(2+3c)=-2(2c-1)+10

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Solution for 4(2+3c)=-2(2c-1)+10 equation:


Simplifying
4(2 + 3c) = -2(2c + -1) + 10
(2 * 4 + 3c * 4) = -2(2c + -1) + 10
(8 + 12c) = -2(2c + -1) + 10

Reorder the terms:
8 + 12c = -2(-1 + 2c) + 10
8 + 12c = (-1 * -2 + 2c * -2) + 10
8 + 12c = (2 + -4c) + 10

Reorder the terms:
8 + 12c = 2 + 10 + -4c

Combine like terms: 2 + 10 = 12
8 + 12c = 12 + -4c

Solving
8 + 12c = 12 + -4c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '4c' to each side of the equation.
8 + 12c + 4c = 12 + -4c + 4c

Combine like terms: 12c + 4c = 16c
8 + 16c = 12 + -4c + 4c

Combine like terms: -4c + 4c = 0
8 + 16c = 12 + 0
8 + 16c = 12

Add '-8' to each side of the equation.
8 + -8 + 16c = 12 + -8

Combine like terms: 8 + -8 = 0
0 + 16c = 12 + -8
16c = 12 + -8

Combine like terms: 12 + -8 = 4
16c = 4

Divide each side by '16'.
c = 0.25

Simplifying
c = 0.25

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