4(2+3c)=9c+20

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Solution for 4(2+3c)=9c+20 equation: 



4(2+3c)=9c+20

We move all terms to the left:

4(2+3c)-(9c+20)=0

We add all the numbers together, and all the variables

4(3c+2)-(9c+20)=0

We multiply parentheses

12c-(9c+20)+8=0

We get rid of parentheses

12c-9c-20+8=0

We add all the numbers together, and all the variables

3c-12=0

We move all terms containing c to the left, all other terms to the right

3c=12

c=12/3

c=4

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