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4(2+3x)=3(2x-4)
We move all terms to the left:
4(2+3x)-(3(2x-4))=0
We add all the numbers together, and all the variables
4(3x+2)-(3(2x-4))=0
We multiply parentheses
12x-(3(2x-4))+8=0
We calculate terms in parentheses: -(3(2x-4)), so:We get rid of parentheses
3(2x-4)
We multiply parentheses
6x-12
Back to the equation:
-(6x-12)
12x-6x+12+8=0
We add all the numbers together, and all the variables
6x+20=0
We move all terms containing x to the left, all other terms to the right
6x=-20
x=-20/6
x=-3+1/3
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