4(2+3x)=3(2x-4)

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Solution for 4(2+3x)=3(2x-4) equation: 



4(2+3x)=3(2x-4)

We move all terms to the left:

4(2+3x)-(3(2x-4))=0

We add all the numbers together, and all the variables

4(3x+2)-(3(2x-4))=0

We multiply parentheses

12x-(3(2x-4))+8=0



We calculate terms in parentheses: -(3(2x-4)), so:

3(2x-4)

We multiply parentheses

6x-12

Back to the equation:

-(6x-12)



We get rid of parentheses

12x-6x+12+8=0

We add all the numbers together, and all the variables

6x+20=0

We move all terms containing x to the left, all other terms to the right

6x=-20

x=-20/6

x=-3+1/3

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