4(2+3y)+7y=27

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Solution for 4(2+3y)+7y=27 equation: 



4(2+3y)+7y=27

We move all terms to the left:

4(2+3y)+7y-(27)=0

We add all the numbers together, and all the variables

4(3y+2)+7y-27=0

We add all the numbers together, and all the variables

7y+4(3y+2)-27=0

We multiply parentheses

7y+12y+8-27=0

We add all the numbers together, and all the variables

19y-19=0

We move all terms containing y to the left, all other terms to the right

19y=19

y=19/19

y=1

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