4(2+4k)+(7k+1)8=0

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Solution for 4(2+4k)+(7k+1)8=0 equation: 



4(2+4k)+(7k+1)8=0

We add all the numbers together, and all the variables

4(4k+2)+(7k+1)8=0

We multiply parentheses

16k+56k+8+8=0

We add all the numbers together, and all the variables

72k+16=0

We move all terms containing k to the left, all other terms to the right

72k=-16

k=-16/72

k=-2/9

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