4(2+5v)+3v=4v+27

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Solution for 4(2+5v)+3v=4v+27 equation: 



4(2+5v)+3v=4v+27

We move all terms to the left:

4(2+5v)+3v-(4v+27)=0

We add all the numbers together, and all the variables

4(5v+2)+3v-(4v+27)=0

We add all the numbers together, and all the variables

3v+4(5v+2)-(4v+27)=0

We multiply parentheses

3v+20v-(4v+27)+8=0

We get rid of parentheses

3v+20v-4v-27+8=0

We add all the numbers together, and all the variables

19v-19=0

We move all terms containing v to the left, all other terms to the right

19v=19

v=19/19

v=1

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