4(2+b)+(-2b)+(-1)-(2+b)-b=5

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Solution for 4(2+b)+(-2b)+(-1)-(2+b)-b=5 equation: 


Simplifying
4(2 + b) + (-2b) + (-1) + -1(2 + b) + -1b = 5
(2 * 4 + b * 4) + (-2b) + (-1) + -1(2 + b) + -1b = 5
(8 + 4b) + (-2b) + (-1) + -1(2 + b) + -1b = 5
8 + 4b + (-2b) + -1 + -1(2 + b) + -1b = 5
8 + 4b + (-2b) + -1 + (2 * -1 + b * -1) + -1b = 5
8 + 4b + (-2b) + -1 + (-2 + -1b) + -1b = 5

Reorder the terms:
8 + -1 + -2 + 4b + (-2b) + -1b + -1b = 5

Combine like terms: 8 + -1 = 7
7 + -2 + 4b + (-2b) + -1b + -1b = 5

Combine like terms: 7 + -2 = 5
5 + 4b + (-2b) + -1b + -1b = 5

Combine like terms: 4b + (-2b) = 2b
5 + 2b + -1b + -1b = 5

Combine like terms: 2b + -1b = 1b
5 + 1b + -1b = 5

Combine like terms: 1b + -1b = 0
5 + 0 = 5
5 = 5

Add '-5' to each side of the equation.
5 + -5 = 5 + -5

Combine like terms: 5 + -5 = 0
0 = 5 + -5

Combine like terms: 5 + -5 = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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