4(2+b)=4(2+b)

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Solution for 4(2+b)=4(2+b) equation: 



4(2+b)=4(2+b)

We move all terms to the left:

4(2+b)-(4(2+b))=0

We add all the numbers together, and all the variables

4(b+2)-(4(b+2))=0

We multiply parentheses

4b-(4(b+2))+8=0



We calculate terms in parentheses: -(4(b+2)), so:

4(b+2)

We multiply parentheses

4b+8

Back to the equation:

-(4b+8)



We get rid of parentheses

4b-4b-8+8=0

We add all the numbers together, and all the variables

=0

b=0/1

b=0

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