4(2+c)=3(c-4)

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Solution for 4(2+c)=3(c-4) equation: 


Simplifying
4(2 + c) = 3(c + -4)
(2 * 4 + c * 4) = 3(c + -4)
(8 + 4c) = 3(c + -4)

Reorder the terms:
8 + 4c = 3(-4 + c)
8 + 4c = (-4 * 3 + c * 3)
8 + 4c = (-12 + 3c)

Solving
8 + 4c = -12 + 3c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-3c' to each side of the equation.
8 + 4c + -3c = -12 + 3c + -3c

Combine like terms: 4c + -3c = 1c
8 + 1c = -12 + 3c + -3c

Combine like terms: 3c + -3c = 0
8 + 1c = -12 + 0
8 + 1c = -12

Add '-8' to each side of the equation.
8 + -8 + 1c = -12 + -8

Combine like terms: 8 + -8 = 0
0 + 1c = -12 + -8
1c = -12 + -8

Combine like terms: -12 + -8 = -20
1c = -20

Divide each side by '1'.
c = -20

Simplifying
c = -20

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