4(2+m-4)=32

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Solution for 4(2+m-4)=32 equation: 



4(2+m-4)=32

We move all terms to the left:

4(2+m-4)-(32)=0

We add all the numbers together, and all the variables

4(m-2)-32=0

We multiply parentheses

4m-8-32=0

We add all the numbers together, and all the variables

4m-40=0

We move all terms containing m to the left, all other terms to the right

4m=40

m=40/4

m=10

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