4(2+n)=2(2n-1)+10

Solution for 4(2+n)=2(2n-1)+10 equation:

4(2+n)=2(2n-1)+10

We move all terms to the left:

4(2+n)-(2(2n-1)+10)=0

We add all the numbers together, and all the variables

4(n+2)-(2(2n-1)+10)=0

We multiply parentheses

4n-(2(2n-1)+10)+8=0


We calculate terms in parentheses: -(2(2n-1)+10), so:

2(2n-1)+10

We multiply parentheses

4n-2+10

We add all the numbers together, and all the variables

4n+8

Back to the equation:

-(4n+8)


We get rid of parentheses

4n-4n-8+8=0

We add all the numbers together, and all the variables

=0

n=0/1

n=0