4(2+t)-21=7t-6

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Solution for 4(2+t)-21=7t-6 equation: 



4(2+t)-21=7t-6

We move all terms to the left:

4(2+t)-21-(7t-6)=0

We add all the numbers together, and all the variables

4(t+2)-(7t-6)-21=0

We multiply parentheses

4t-(7t-6)+8-21=0

We get rid of parentheses

4t-7t+6+8-21=0

We add all the numbers together, and all the variables

-3t-7=0

We move all terms containing t to the left, all other terms to the right

-3t=7

t=7/-3

t=-2+1/3

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