4(2+w)=5(w+1)+w-1

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Solution for 4(2+w)=5(w+1)+w-1 equation: 



4(2+w)=5(w+1)+w-1

We move all terms to the left:

4(2+w)-(5(w+1)+w-1)=0

We add all the numbers together, and all the variables

4(w+2)-(5(w+1)+w-1)=0

We multiply parentheses

4w-(5(w+1)+w-1)+8=0



We calculate terms in parentheses: -(5(w+1)+w-1), so:

5(w+1)+w-1

We add all the numbers together, and all the variables

w+5(w+1)-1

We multiply parentheses

w+5w+5-1

We add all the numbers together, and all the variables

6w+4

Back to the equation:

-(6w+4)



We get rid of parentheses

4w-6w-4+8=0

We add all the numbers together, and all the variables

-2w+4=0

We move all terms containing w to the left, all other terms to the right

-2w=-4

w=-4/-2

w=+2

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