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4(2+x)=3(1+x)
We move all terms to the left:
4(2+x)-(3(1+x))=0
We add all the numbers together, and all the variables
4(x+2)-(3(x+1))=0
We multiply parentheses
4x-(3(x+1))+8=0
We calculate terms in parentheses: -(3(x+1)), so:We get rid of parentheses
3(x+1)
We multiply parentheses
3x+3
Back to the equation:
-(3x+3)
4x-3x-3+8=0
We add all the numbers together, and all the variables
x+5=0
We move all terms containing x to the left, all other terms to the right
x=-5
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