4(2+x)=4(7+2x)+5

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Solution for 4(2+x)=4(7+2x)+5 equation: 



4(2+x)=4(7+2x)+5

We move all terms to the left:

4(2+x)-(4(7+2x)+5)=0

We add all the numbers together, and all the variables

4(x+2)-(4(2x+7)+5)=0

We multiply parentheses

4x-(4(2x+7)+5)+8=0



We calculate terms in parentheses: -(4(2x+7)+5), so:

4(2x+7)+5

We multiply parentheses

8x+28+5

We add all the numbers together, and all the variables

8x+33

Back to the equation:

-(8x+33)



We get rid of parentheses

4x-8x-33+8=0

We add all the numbers together, and all the variables

-4x-25=0

We move all terms containing x to the left, all other terms to the right

-4x=25

x=25/-4

x=-6+1/4

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