4(2-1)-6=6(2z+3)-12

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Solution for 4(2-1)-6=6(2z+3)-12 equation: 



4(2-1)-6=6(2z+3)-12

We move all terms to the left:

4(2-1)-6-(6(2z+3)-12)=0

We add all the numbers together, and all the variables

-(6(2z+3)-12)-6+41=0

We add all the numbers together, and all the variables

-(6(2z+3)-12)+35=0



We calculate terms in parentheses: -(6(2z+3)-12), so:

6(2z+3)-12

We multiply parentheses

12z+18-12

We add all the numbers together, and all the variables

12z+6

Back to the equation:

-(12z+6)



We get rid of parentheses

-12z-6+35=0

We add all the numbers together, and all the variables

-12z+29=0

We move all terms containing z to the left, all other terms to the right

-12z=-29

z=-29/-12

z=2+5/12

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