4(2-3)=3(s+1)

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Solution for 4(2-3)=3(s+1) equation: 



4(2-3)=3(s+1)

We move all terms to the left:

4(2-3)-(3(s+1))=0

We add all the numbers together, and all the variables

-(3(s+1))+4(-1)=0

We add all the numbers together, and all the variables

-(3(s+1))-4=0



We calculate terms in parentheses: -(3(s+1)), so:

3(s+1)

We multiply parentheses

3s+3

Back to the equation:

-(3s+3)



We get rid of parentheses

-3s-3-4=0

We add all the numbers together, and all the variables

-3s-7=0

We move all terms containing s to the left, all other terms to the right

-3s=7

s=7/-3

s=-2+1/3

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