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4(2-3x)=2(3x-5)
We move all terms to the left:
4(2-3x)-(2(3x-5))=0
We add all the numbers together, and all the variables
4(-3x+2)-(2(3x-5))=0
We multiply parentheses
-12x-(2(3x-5))+8=0
We calculate terms in parentheses: -(2(3x-5)), so:We get rid of parentheses
2(3x-5)
We multiply parentheses
6x-10
Back to the equation:
-(6x-10)
-12x-6x+10+8=0
We add all the numbers together, and all the variables
-18x+18=0
We move all terms containing x to the left, all other terms to the right
-18x=-18
x=-18/-18
x=1
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