4(2-4r)-3r=65

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Solution for 4(2-4r)-3r=65 equation: 



4(2-4r)-3r=65

We move all terms to the left:

4(2-4r)-3r-(65)=0

We add all the numbers together, and all the variables

4(-4r+2)-3r-65=0

We add all the numbers together, and all the variables

-3r+4(-4r+2)-65=0

We multiply parentheses

-3r-16r+8-65=0

We add all the numbers together, and all the variables

-19r-57=0

We move all terms containing r to the left, all other terms to the right

-19r=57

r=57/-19

r=-3

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