4(2-a)-3a+10=19

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Solution for 4(2-a)-3a+10=19 equation: 



4(2-a)-3a+10=19

We move all terms to the left:

4(2-a)-3a+10-(19)=0

We add all the numbers together, and all the variables

4(-1a+2)-3a+10-19=0

We add all the numbers together, and all the variables

-3a+4(-1a+2)-9=0

We multiply parentheses

-3a-4a+8-9=0

We add all the numbers together, and all the variables

-7a-1=0

We move all terms containing a to the left, all other terms to the right

-7a=1

a=1/-7

a=-1/7

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