4(2-b)+15=3(b+3)

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Solution for 4(2-b)+15=3(b+3) equation: 



4(2-b)+15=3(b+3)

We move all terms to the left:

4(2-b)+15-(3(b+3))=0

We add all the numbers together, and all the variables

4(-1b+2)-(3(b+3))+15=0

We multiply parentheses

-4b-(3(b+3))+8+15=0



We calculate terms in parentheses: -(3(b+3)), so:

3(b+3)

We multiply parentheses

3b+9

Back to the equation:

-(3b+9)



We add all the numbers together, and all the variables

-4b-(3b+9)+23=0

We get rid of parentheses

-4b-3b-9+23=0

We add all the numbers together, and all the variables

-7b+14=0

We move all terms containing b to the left, all other terms to the right

-7b=-14

b=-14/-7

b=+2

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