4(2-d)=3(2+d)

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Solution for 4(2-d)=3(2+d) equation: 



4(2-d)=3(2+d)

We move all terms to the left:

4(2-d)-(3(2+d))=0

We add all the numbers together, and all the variables

4(-1d+2)-(3(d+2))=0

We multiply parentheses

-4d-(3(d+2))+8=0



We calculate terms in parentheses: -(3(d+2)), so:

3(d+2)

We multiply parentheses

3d+6

Back to the equation:

-(3d+6)



We get rid of parentheses

-4d-3d-6+8=0

We add all the numbers together, and all the variables

-7d+2=0

We move all terms containing d to the left, all other terms to the right

-7d=-2

d=-2/-7

d=2/7

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