4(2-n)=41

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Solution for 4(2-n)=41 equation:



4(2-n)=41
We move all terms to the left:
4(2-n)-(41)=0
We add all the numbers together, and all the variables
4(-1n+2)-41=0
We multiply parentheses
-4n+8-41=0
We add all the numbers together, and all the variables
-4n-33=0
We move all terms containing n to the left, all other terms to the right
-4n=33
n=33/-4
n=-8+1/4

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