4(2-n)=41

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Solution for 4(2-n)=41 equation: 



4(2-n)=41

We move all terms to the left:

4(2-n)-(41)=0

We add all the numbers together, and all the variables

4(-1n+2)-41=0

We multiply parentheses

-4n+8-41=0

We add all the numbers together, and all the variables

-4n-33=0

We move all terms containing n to the left, all other terms to the right

-4n=33

n=33/-4

n=-8+1/4

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