4(2-t)=3(4+t)+10

Solution for 4(2-t)=3(4+t)+10 equation:

4(2-t)=3(4+t)+10

We move all terms to the left:

4(2-t)-(3(4+t)+10)=0

We add all the numbers together, and all the variables

4(-1t+2)-(3(t+4)+10)=0

We multiply parentheses

-4t-(3(t+4)+10)+8=0


We calculate terms in parentheses: -(3(t+4)+10), so:

3(t+4)+10

We multiply parentheses

3t+12+10

We add all the numbers together, and all the variables

3t+22

Back to the equation:

-(3t+22)


We get rid of parentheses

-4t-3t-22+8=0

We add all the numbers together, and all the variables

-7t-14=0

We move all terms containing t to the left, all other terms to the right

-7t=14

t=14/-7

t=-2