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4(2-t)=3(4+t)+10
We move all terms to the left:
4(2-t)-(3(4+t)+10)=0
We add all the numbers together, and all the variables
4(-1t+2)-(3(t+4)+10)=0
We multiply parentheses
-4t-(3(t+4)+10)+8=0
We calculate terms in parentheses: -(3(t+4)+10), so:We get rid of parentheses
3(t+4)+10
We multiply parentheses
3t+12+10
We add all the numbers together, and all the variables
3t+22
Back to the equation:
-(3t+22)
-4t-3t-22+8=0
We add all the numbers together, and all the variables
-7t-14=0
We move all terms containing t to the left, all other terms to the right
-7t=14
t=14/-7
t=-2
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