4(2-x)+1=2x+2-5(1+4x)

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Solution for 4(2-x)+1=2x+2-5(1+4x) equation: 



4(2-x)+1=2x+2-5(1+4x)

We move all terms to the left:

4(2-x)+1-(2x+2-5(1+4x))=0

We add all the numbers together, and all the variables

4(-1x+2)-(2x+2-5(4x+1))+1=0

We multiply parentheses

-4x-(2x+2-5(4x+1))+8+1=0



We calculate terms in parentheses: -(2x+2-5(4x+1)), so:

2x+2-5(4x+1)

determiningTheFunctionDomain
2x-5(4x+1)+2

We multiply parentheses

2x-20x-5+2

We add all the numbers together, and all the variables

-18x-3

Back to the equation:

-(-18x-3)



We add all the numbers together, and all the variables

-4x-(-18x-3)+9=0

We get rid of parentheses

-4x+18x+3+9=0

We add all the numbers together, and all the variables

14x+12=0

We move all terms containing x to the left, all other terms to the right

14x=-12

x=-12/14

x=-6/7

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