4(2-x)=12x+2-5(1-4x)

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Solution for 4(2-x)=12x+2-5(1-4x) equation: 



4(2-x)=12x+2-5(1-4x)

We move all terms to the left:

4(2-x)-(12x+2-5(1-4x))=0

We add all the numbers together, and all the variables

4(-1x+2)-(12x+2-5(-4x+1))=0

We multiply parentheses

-4x-(12x+2-5(-4x+1))+8=0



We calculate terms in parentheses: -(12x+2-5(-4x+1)), so:

12x+2-5(-4x+1)

determiningTheFunctionDomain
12x-5(-4x+1)+2

We multiply parentheses

12x+20x-5+2

We add all the numbers together, and all the variables

32x-3

Back to the equation:

-(32x-3)



We get rid of parentheses

-4x-32x+3+8=0

We add all the numbers together, and all the variables

-36x+11=0

We move all terms containing x to the left, all other terms to the right

-36x=-11

x=-11/-36

x=11/36

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