4(2-y)+3y=(y-4)

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Solution for 4(2-y)+3y=(y-4) equation: 



4(2-y)+3y=(y-4)

We move all terms to the left:

4(2-y)+3y-((y-4))=0

We add all the numbers together, and all the variables

4(-1y+2)+3y-((y-4))=0

We add all the numbers together, and all the variables

3y+4(-1y+2)-((y-4))=0

We multiply parentheses

3y-4y-((y-4))+8=0



We calculate terms in parentheses: -((y-4)), so:

(y-4)

We get rid of parentheses

y-4

Back to the equation:

-(y-4)



We add all the numbers together, and all the variables

-1y-(y-4)+8=0

We get rid of parentheses

-1y-y+4+8=0

We add all the numbers together, and all the variables

-2y+12=0

We move all terms containing y to the left, all other terms to the right

-2y=-12

y=-12/-2

y=+6

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