4(2/3)n=0

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Solution for 4(2/3)n=0 equation: 



4(2/3)n=0



Domain of the equation: 3)n!=0

n!=0/1

n!=0

n∈R



We add all the numbers together, and all the variables

4(+2/3)n=0

We multiply parentheses

8n^2=0

a = 8; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·8·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$n=\frac{-b}{2a}=\frac{0}{16}=0$

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