4(20+5d)=2(50+5d)

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Solution for 4(20+5d)=2(50+5d) equation: 



4(20+5d)=2(50+5d)

We move all terms to the left:

4(20+5d)-(2(50+5d))=0

We add all the numbers together, and all the variables

4(5d+20)-(2(5d+50))=0

We multiply parentheses

20d-(2(5d+50))+80=0



We calculate terms in parentheses: -(2(5d+50)), so:

2(5d+50)

We multiply parentheses

10d+100

Back to the equation:

-(10d+100)



We get rid of parentheses

20d-10d-100+80=0

We add all the numbers together, and all the variables

10d-20=0

We move all terms containing d to the left, all other terms to the right

10d=20

d=20/10

d=2

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