4(20+5d)=2(50-5d)

Solution for 4(20+5d)=2(50-5d) equation:

4(20+5d)=2(50-5d)

We move all terms to the left:

4(20+5d)-(2(50-5d))=0

We add all the numbers together, and all the variables

4(5d+20)-(2(-5d+50))=0

We multiply parentheses

20d-(2(-5d+50))+80=0


We calculate terms in parentheses: -(2(-5d+50)), so:

2(-5d+50)

We multiply parentheses

-10d+100

Back to the equation:

-(-10d+100)


We get rid of parentheses

20d+10d-100+80=0

We add all the numbers together, and all the variables

30d-20=0

We move all terms containing d to the left, all other terms to the right

30d=20

d=20/30

d=2/3