4(20y+40)+80=5(100y-60)-380

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Solution for 4(20y+40)+80=5(100y-60)-380 equation: 



4(20y+40)+80=5(100y-60)-380

We move all terms to the left:

4(20y+40)+80-(5(100y-60)-380)=0

We multiply parentheses

80y-(5(100y-60)-380)+160+80=0



We calculate terms in parentheses: -(5(100y-60)-380), so:

5(100y-60)-380

We multiply parentheses

500y-300-380

We add all the numbers together, and all the variables

500y-680

Back to the equation:

-(500y-680)



We add all the numbers together, and all the variables

80y-(500y-680)+240=0

We get rid of parentheses

80y-500y+680+240=0

We add all the numbers together, and all the variables

-420y+920=0

We move all terms containing y to the left, all other terms to the right

-420y=-920

y=-920/-420

y=2+4/21

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