4(2C+3)-3(4-C)=2(C-4)-2

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Solution for 4(2C+3)-3(4-C)=2(C-4)-2 equation: 


Simplifying
4(2C + 3) + -3(4 + -1C) = 2(C + -4) + -2

Reorder the terms:
4(3 + 2C) + -3(4 + -1C) = 2(C + -4) + -2
(3 * 4 + 2C * 4) + -3(4 + -1C) = 2(C + -4) + -2
(12 + 8C) + -3(4 + -1C) = 2(C + -4) + -2
12 + 8C + (4 * -3 + -1C * -3) = 2(C + -4) + -2
12 + 8C + (-12 + 3C) = 2(C + -4) + -2

Reorder the terms:
12 + -12 + 8C + 3C = 2(C + -4) + -2

Combine like terms: 12 + -12 = 0
0 + 8C + 3C = 2(C + -4) + -2
8C + 3C = 2(C + -4) + -2

Combine like terms: 8C + 3C = 11C
11C = 2(C + -4) + -2

Reorder the terms:
11C = 2(-4 + C) + -2
11C = (-4 * 2 + C * 2) + -2
11C = (-8 + 2C) + -2

Reorder the terms:
11C = -8 + -2 + 2C

Combine like terms: -8 + -2 = -10
11C = -10 + 2C

Solving
11C = -10 + 2C

Solving for variable 'C'.

Move all terms containing C to the left, all other terms to the right.

Add '-2C' to each side of the equation.
11C + -2C = -10 + 2C + -2C

Combine like terms: 11C + -2C = 9C
9C = -10 + 2C + -2C

Combine like terms: 2C + -2C = 0
9C = -10 + 0
9C = -10

Divide each side by '9'.
C = -1.111111111

Simplifying
C = -1.111111111

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