4(2Z+2)-1=7(z-1)+16

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Solution for 4(2Z+2)-1=7(z-1)+16 equation:


Simplifying
4(2Z + 2) + -1 = 7(z + -1) + 16

Reorder the terms:
4(2 + 2Z) + -1 = 7(z + -1) + 16
(2 * 4 + 2Z * 4) + -1 = 7(z + -1) + 16
(8 + 8Z) + -1 = 7(z + -1) + 16

Reorder the terms:
8 + -1 + 8Z = 7(z + -1) + 16

Combine like terms: 8 + -1 = 7
7 + 8Z = 7(z + -1) + 16

Reorder the terms:
7 + 8Z = 7(-1 + z) + 16
7 + 8Z = (-1 * 7 + z * 7) + 16
7 + 8Z = (-7 + 7z) + 16

Reorder the terms:
7 + 8Z = -7 + 16 + 7z

Combine like terms: -7 + 16 = 9
7 + 8Z = 9 + 7z

Solving
7 + 8Z = 9 + 7z

Solving for variable 'Z'.

Move all terms containing Z to the left, all other terms to the right.

Add '-7' to each side of the equation.
7 + -7 + 8Z = 9 + -7 + 7z

Combine like terms: 7 + -7 = 0
0 + 8Z = 9 + -7 + 7z
8Z = 9 + -7 + 7z

Combine like terms: 9 + -7 = 2
8Z = 2 + 7z

Divide each side by '8'.
Z = 0.25 + 0.875z

Simplifying
Z = 0.25 + 0.875z

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