4(2a+3)-4(3a-6)=15

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Solution for 4(2a+3)-4(3a-6)=15 equation: 



4(2a+3)-4(3a-6)=15

We move all terms to the left:

4(2a+3)-4(3a-6)-(15)=0

We multiply parentheses

8a-12a+12+24-15=0

We add all the numbers together, and all the variables

-4a+21=0

We move all terms containing a to the left, all other terms to the right

-4a=-21

a=-21/-4

a=5+1/4

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