4(2a+3)=-3(a-1)+42

Solution for 4(2a+3)=-3(a-1)+42 equation:

4(2a+3)=-3(a-1)+42

We move all terms to the left:

4(2a+3)-(-3(a-1)+42)=0

We multiply parentheses

8a-(-3(a-1)+42)+12=0


We calculate terms in parentheses: -(-3(a-1)+42), so:

-3(a-1)+42

We multiply parentheses

-3a+3+42

We add all the numbers together, and all the variables

-3a+45

Back to the equation:

-(-3a+45)


We get rid of parentheses

8a+3a-45+12=0

We add all the numbers together, and all the variables

11a-33=0

We move all terms containing a to the left, all other terms to the right

11a=33

a=33/11

a=3