4(2a+3)=3(a-1)+31=

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Solution for 4(2a+3)=3(a-1)+31= equation: 



4(2a+3)=3(a-1)+31=

We move all terms to the left:

4(2a+3)-(3(a-1)+31)=0

We multiply parentheses

8a-(3(a-1)+31)+12=0



We calculate terms in parentheses: -(3(a-1)+31), so:

3(a-1)+31

We multiply parentheses

3a-3+31

We add all the numbers together, and all the variables

3a+28

Back to the equation:

-(3a+28)



We get rid of parentheses

8a-3a-28+12=0

We add all the numbers together, and all the variables

5a-16=0

We move all terms containing a to the left, all other terms to the right

5a=16

a=16/5

a=3+1/5

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