4(2a+b-3c)=

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Solution for 4(2a+b-3c)= equation:


Simplifying
4(2a + b + -3c) = 0
(2a * 4 + b * 4 + -3c * 4) = 0
(8a + 4b + -12c) = 0

Solving
8a + 4b + -12c = 0

Solving for variable 'a'.

Move all terms containing a to the left, all other terms to the right.

Add '-4b' to each side of the equation.
8a + 4b + -4b + -12c = 0 + -4b

Combine like terms: 4b + -4b = 0
8a + 0 + -12c = 0 + -4b
8a + -12c = 0 + -4b
Remove the zero:
8a + -12c = -4b

Add '12c' to each side of the equation.
8a + -12c + 12c = -4b + 12c

Combine like terms: -12c + 12c = 0
8a + 0 = -4b + 12c
8a = -4b + 12c

Divide each side by '8'.
a = -0.5b + 1.5c

Simplifying
a = -0.5b + 1.5c

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