4(2a-1)+a=3(3a-1)-1

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Solution for 4(2a-1)+a=3(3a-1)-1 equation:


Simplifying
4(2a + -1) + a = 3(3a + -1) + -1

Reorder the terms:
4(-1 + 2a) + a = 3(3a + -1) + -1
(-1 * 4 + 2a * 4) + a = 3(3a + -1) + -1
(-4 + 8a) + a = 3(3a + -1) + -1

Combine like terms: 8a + a = 9a
-4 + 9a = 3(3a + -1) + -1

Reorder the terms:
-4 + 9a = 3(-1 + 3a) + -1
-4 + 9a = (-1 * 3 + 3a * 3) + -1
-4 + 9a = (-3 + 9a) + -1

Reorder the terms:
-4 + 9a = -3 + -1 + 9a

Combine like terms: -3 + -1 = -4
-4 + 9a = -4 + 9a

Add '4' to each side of the equation.
-4 + 4 + 9a = -4 + 4 + 9a

Combine like terms: -4 + 4 = 0
0 + 9a = -4 + 4 + 9a
9a = -4 + 4 + 9a

Combine like terms: -4 + 4 = 0
9a = 0 + 9a
9a = 9a

Add '-9a' to each side of the equation.
9a + -9a = 9a + -9a

Combine like terms: 9a + -9a = 0
0 = 9a + -9a

Combine like terms: 9a + -9a = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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