4(2a-3)+5=-6(a-4)+12a-31

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Solution for 4(2a-3)+5=-6(a-4)+12a-31 equation: 



4(2a-3)+5=-6(a-4)+12a-31

We move all terms to the left:

4(2a-3)+5-(-6(a-4)+12a-31)=0

We multiply parentheses

8a-(-6(a-4)+12a-31)-12+5=0



We calculate terms in parentheses: -(-6(a-4)+12a-31), so:

-6(a-4)+12a-31

We add all the numbers together, and all the variables

12a-6(a-4)-31

We multiply parentheses

12a-6a+24-31

We add all the numbers together, and all the variables

6a-7

Back to the equation:

-(6a-7)



We add all the numbers together, and all the variables

8a-(6a-7)-7=0

We get rid of parentheses

8a-6a+7-7=0

We add all the numbers together, and all the variables

2a=0

a=0/2

a=0

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