4(2a-3)-(a+7)-4a+6=5(a-2)-3a+7(2a+2)

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Solution for 4(2a-3)-(a+7)-4a+6=5(a-2)-3a+7(2a+2) equation:



4(2a-3)-(a+7)-4a+6=5(a-2)-3a+7(2a+2)
We move all terms to the left:
4(2a-3)-(a+7)-4a+6-(5(a-2)-3a+7(2a+2))=0
We add all the numbers together, and all the variables
-4a+4(2a-3)-(a+7)-(5(a-2)-3a+7(2a+2))+6=0
We multiply parentheses
-4a+8a-(a+7)-(5(a-2)-3a+7(2a+2))-12+6=0
We get rid of parentheses
-4a+8a-a-(5(a-2)-3a+7(2a+2))-7-12+6=0
We calculate terms in parentheses: -(5(a-2)-3a+7(2a+2)), so:
5(a-2)-3a+7(2a+2)
We add all the numbers together, and all the variables
-3a+5(a-2)+7(2a+2)
We multiply parentheses
-3a+5a+14a-10+14
We add all the numbers together, and all the variables
16a+4
Back to the equation:
-(16a+4)
We add all the numbers together, and all the variables
3a-(16a+4)-13=0
We get rid of parentheses
3a-16a-4-13=0
We add all the numbers together, and all the variables
-13a-17=0
We move all terms containing a to the left, all other terms to the right
-13a=17
a=17/-13
a=-1+4/13

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