4(2a-3)-4a=4(a-5)

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Solution for 4(2a-3)-4a=4(a-5) equation:


Simplifying
4(2a + -3) + -4a = 4(a + -5)

Reorder the terms:
4(-3 + 2a) + -4a = 4(a + -5)
(-3 * 4 + 2a * 4) + -4a = 4(a + -5)
(-12 + 8a) + -4a = 4(a + -5)

Combine like terms: 8a + -4a = 4a
-12 + 4a = 4(a + -5)

Reorder the terms:
-12 + 4a = 4(-5 + a)
-12 + 4a = (-5 * 4 + a * 4)
-12 + 4a = (-20 + 4a)

Add '-4a' to each side of the equation.
-12 + 4a + -4a = -20 + 4a + -4a

Combine like terms: 4a + -4a = 0
-12 + 0 = -20 + 4a + -4a
-12 = -20 + 4a + -4a

Combine like terms: 4a + -4a = 0
-12 = -20 + 0
-12 = -20

Solving
-12 = -20

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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