4(2a-8)=1/7(49a+79

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Solution for 4(2a-8)=1/7(49a+79 equation: 



4(2a-8)=1/7(49a+79

We move all terms to the left:

4(2a-8)-(1/7(49a+79)=0



Domain of the equation: 7(49a+79)!=0

a∈R



We multiply parentheses

8a-(1/7(49a+79)-32=0

We multiply all the terms by the denominator


8a*7(49a+79)-32-(1=0

We add all the numbers together, and all the variables

8a*7(49a+79)=0

Wy multiply elements

56a^2(4=0

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